Nothing revolutionary, just more smart method of generating Heronian triangles using Leonard Euler method
https://github.com/renyxadarox/sheron/b ... sheron2.py
Die Suche ergab 102 Treffer
- 11.07.2022 20:58
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Heronian Triangles with Square Sides
- Antworten: 3
- Zugriffe: 9075
- 27.04.2021 20:34
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Heronian Triangles with Square Sides
- Antworten: 3
- Zugriffe: 9075
- 12.02.2021 09:34
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Heronian Triangles with Square Sides
- Antworten: 3
- Zugriffe: 9075
[sub-project] Heronian Triangles with Square Sides
Abstract If Perfect cuboid exists, the squares of 3 its face diagonals should construct a Heronian triangle. Proof: photo_2021-02-12_10-19-32.jpg Note: Heronian triangle is a triangle that has side lengths and area that are all integers. At the moment it is known about only two Heronian triangles w...
- 30.10.2018 20:52
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
- 29.10.2018 22:33
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
- 27.10.2018 16:42
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
- 25.10.2018 20:57
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
Re: [sub-project] Perfect cuboid
x3mEn I know about you had showed. But I told about other equation whith new integer variable x, which included sqr(16a^2b^2c^2g^2). The equation will be TRUE only in case when d,e,f will correspond perfect brick's face diagonals. By means of transformations and finding the roots of the equation, w...
- 25.10.2018 15:14
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
Re: [sub-project] Perfect cuboid
Decision of equation in integers will be equal to full task, because if we will have d,e,f , then we can find all the rest. We can find g and then we can find a,b,c. You are not right. When you have a system of Diophantine X equations with Y variables, theoretically you can simplify it to an equati...
- 25.10.2018 08:40
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
Re: [sub-project] Perfect cuboid
the fourh exponent is not too big? It's time to talk about how Math works. :) With the help of strict math logic of equivalent expressions you transfered from the given system of 4 Diophantine equations to consequent (and, btw, not necessary equivalent to input system) expression, which says: "If t...
- 24.10.2018 21:41
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
Re: [sub-project] Perfect cuboid
Zak, you are muddling up 'necessary' and 'enough'. If undersquare expression is 2f^2e^2, yes, it's enough to aquire z as a full square of the sum or the difference of f^2 and e^2. But, is it necessary? No. There are a lot of other expressions binding f and e which are a full square too. The world is...
- 23.10.2018 21:17
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
Re: [sub-project] Perfect cuboid
Some ideas regarding the last equation. As far as One edge, two face diagonals and the body diagonal must be odd, one edge and the remaining face diagonal must be divisible by 4, and the remaining edge must be divisible by 16. Two edges must have length divisible by 3 and at least one of those edges...
- 23.10.2018 09:57
- Forum: Fehler, Wünsche / Bugs, Wishes
- Thema: [sub-project] Perfect cuboid
- Antworten: 260
- Zugriffe: 312377
Re: [sub-project] Perfect cuboid
Zak, no problem, buу Wolfram|Alpha Pro to get the proof.