Die Suche ergab 110 Treffer

von Zak
29.05.2019 12:12
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
I already found that there is one case when left part of double inequality not performed. It is folowed that PC exists. Nevertheless thank you.
von Zak
28.05.2019 08:47
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
Hi
This link to my proof: http://wdfiles.ru/ikeQ
Can you chek it, please.
von Zak
06.01.2019 13:03
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
Hi! How are the searches going? In the project statistics, the progress so far seems to be unresultative... My own brutal force application still brought nothing too. May be this can be useful to you:
new.png
new.png (154.29 KiB) 17297 mal betrachtet
von Zak
13.12.2018 15:16
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
e10.JPG
e10.JPG (68.31 KiB) 17834 mal betrachtet
von Zak
08.12.2018 07:28
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

One of the face diagonals is divisible by 4, and I had every right to write: (defg)^2=16n^2. Is it clear?
Let's transform both last equations to the reduced form and try to determine the integer roots:
e3.JPG
e3.JPG (66.32 KiB) 17875 mal betrachtet
Are you still in doubt?
von Zak
07.12.2018 22:44
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
Is it clear:
e1.JPG
e1.JPG (48.58 KiB) 48112 mal betrachtet
e2.JPG
e2.JPG (80.56 KiB) 48112 mal betrachtet
?
Do you agree?
von Zak
04.12.2018 21:12
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
Hi! Let me invite you to this discussion:
http://mathhelpplanet.com/viewtopic.php?f=57&t=62956
I think there is not roots among the divisors of the free member of two last equations.
von Zak
30.10.2018 19:08
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
Are you looking for complex values of the face diagonal? It is obvious that if integer values are needed, not complex values, when x^2<4e^4f^4. Insert this condition and try the same one more time, please.
von Zak
28.10.2018 14:53
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
The discriminant cannot be zero, I made a mistake above, there will always be two roots.
Maybe you will be interested to solve the last expression in integers, it will be the geometric mean, then both roots will be integers, if I don't mistake:
g.JPG
g.JPG (18.64 KiB) 48999 mal betrachtet
von Zak
27.10.2018 18:30
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

x3mEn
Try:
m7.JPG
m7.JPG (12.17 KiB) 49048 mal betrachtet
von Zak
27.10.2018 13:01
Forum: Fehler, Wünsche / Bugs, Wishes
Thema: [sub-project] Perfect cuboid
Antworten: 260
Zugriffe: 308029

Re: [sub-project] Perfect cuboid

I think it is possible only in case D=0, d1=d2:
m6.JPG
m6.JPG (20.67 KiB) 49063 mal betrachtet

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