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Zak wrote:Carefully look at the picture. Good luck!
Zak wrote:You don't see that DC'/OH - integer, so AD'/OH' must be integer too?
Zak wrote:Of cause AD/OH' is an integer (2) and DC'/OH is an integer (2). So OH we would carry out to the middle of DC' and OH' we would carry out to the middle of distance, wich parallel and equal to edges AB=AB'. So we analogically can to carry out any perpendicular to the middle of any edge or to the midle of any distance wich parallel of choosen edge. Thus and DC'/OO' must be integer and AD/OO' must be integer and AD'/OO' must be integer. But DC'/AD is ever a non-integer and AD'/AD is ever a non-integer, etc and so on.
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